Help with battery safety!

[leamdown]

I've just purchased my first Mod - a Joyetech Cuboid with 2 Samsung 25r's - and just have a couple of questions regarding the batteries.

The batteries at full charge are 4.2 volts, but say I wanted to push a 0.4 ohm build to 100w. This would draw approx. 16 amps from the batteries but the ohms law calculator says that 6.32 volts comes from the batteries. How does that work with regards to the batteries if they only have 4.2 volts at full charge?

Sorry for such a long post, I just want to make sure I'm as safe as possible when vaping!

Thanks in advance!

 

[TruckinVaper]

Isn't the Cuboid a series mod meaning 8.4V fully charged? Even if it wasn't the voltage can be boosted by the board.
I'm sure it is series so regardless of the ohms of your coil or the amps flowing through it the draw from your fully charged batteries would be 100W over 8.4V, just under twelve amps. This would actually rise as your battery discharges. Say get down to 3.3V each and your still firing at 100W then it would be 100W over 6.6V, just over 15A. This is pulled through both batteries.
If it was a parallel mod it would be 100W over 4.2V, just short of 24A though this would be split between the two batteries so still just under 12A per battery.

 

[EmbraSewerRat]

The circuitry widgets inside the box keep everything ticking over as it should. same as every other VW box the last year or two. A sparky or electronics whizz can advise further on how the widgets do their thing, but you have batteries that are in the top 2 of advised cells to get and they'll be in a well made bit of kit, so you are fine.

Hats off to you for reading your Ohms Law, well impressed! If you ever get to an unregulated device like a tube mech or series/parallel box, I have no worries over your knowledge to cope.