A question about Nicotine strength and Wattage
- Thread starter David567
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zouzounaki
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yes, i think the logic is flawed.
Oh okay, thanks!
D
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No-one round here smokes anything btw. On the topic of nicotine, generally MTL is lower watts high nic and DTL is higher watts and lower nic, but again, it's not hard and fast, just do you...
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I think your mistake is in thinking nicotine strength has a lot to do with the wattage of your device.
What really dictates the amount of power you use is your coil resistance, there are complicated often conflicting accounts of what your power output should be but in simplified terms.
Higher resistance = lower wattage
You don't need to calculate your exact nicotine usage to determine what strength you require, the easiest way to do that is to try it out, if 18mg at 10w with a 1.2ohm coil satisfies your cravings as much as 3mg at 60w with a 0.2ohm coil then you have your answer.
I will add though 18mg freebase is a pretty high dose, usually people only need that much immediately after they quit smoking.
What really dictates the amount of power you use is your coil resistance, there are complicated often conflicting accounts of what your power output should be but in simplified terms.
Higher resistance = lower wattage
You don't need to calculate your exact nicotine usage to determine what strength you require, the easiest way to do that is to try it out, if 18mg at 10w with a 1.2ohm coil satisfies your cravings as much as 3mg at 60w with a 0.2ohm coil then you have your answer.
I will add though 18mg freebase is a pretty high dose, usually people only need that much immediately after they quit smoking.
Yeah, I understand this. My question wasn't from the point of view of what coil or device to use, it was more to do with the actual nicotine consumption.
Because, if you smoke 3mg at 50w, then smoke 3mg at 80w, obviously you're consuming more nicotine because you're inhaling more smoke right?
So if 100w is double the power of 50w, you'd be consuming twice as much nicotine, no?
And so similarly, smoking 3mg at 50w is the same nicotine consumption as 18mg at 10w. Because all you're doing with a lower resistance coil/higher wattage is burning more liquid at one time.
I've been trying to find an answer to this for a while now and can't see how this is incorrect..
zouzounaki
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i think there are a few flawed assumptions.
first, we can’t be sure whether we absorb more or less of the nic that is contained in a big cloud of mostly VG smoke, than we do from a wispy cloud of mostly PG smoke.
second, it’s not necessarily the case that there is direct variation between power and amount of vapour produced.
third, there are many other variables that would have an effect. the type of attie used, coil, airflow etc.
Because, with a lower resistance coil/higher wattage you're burning more juice per puff, or in other words consuming more nicotine
Yeah, those are all very good points..
But vaguely speaking, assuming we are using the same 70/30 mixture, it would be correct to say more wattage = burning more juice = more nicotine consumption, right?
And so by smoking 3mg at 60w, you'd be getting a similar amount of nicotine as you would be on a lower wattage with a higher mg?
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OK so I tried to ignore it but the "smoke" "burning" thing is getting on my nerves lol
Eliquid is not burnt unless there is something very wrong it is vaporised hence why we say vape instead of smoke.
Another of the many variables that determines how much nicotine we are using is vapour volume and density, which are both related to coil surface area. For example a complex coil will produce a higher volume of vapour than a simple round wire coil and with much higher density.
So I say again as far as nicotine dose or usage goes wattage plays a very minor part in that equasion.
As zouzounaki said. There are way too many variables to consider to be able to simplify it down that far.
Also, why do you want to know? It might be easier to answer what you want to know if I can understand why.
No offence but you wouldn't be the first to not except an answer because they asked the wrong question.
Eliquid is not burnt unless there is something very wrong it is vaporised hence why we say vape instead of smoke.
Another of the many variables that determines how much nicotine we are using is vapour volume and density, which are both related to coil surface area. For example a complex coil will produce a higher volume of vapour than a simple round wire coil and with much higher density.
So I say again as far as nicotine dose or usage goes wattage plays a very minor part in that equasion.
As zouzounaki said. There are way too many variables to consider to be able to simplify it down that far.
Also, why do you want to know? It might be easier to answer what you want to know if I can understand why.
No offence but you wouldn't be the first to not except an answer because they asked the wrong question.
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