D
Deleted member 54254
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This is why the phrase "adjust to taste" is generally applied to these situations, people demand answers when experimentation is the only way to work it all out...
A question about Nicotine strength and Wattage
- Thread starter David567
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zouzounaki
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- Dec 13, 2016
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yes to the first question, not necessarily to the second question.
P
Phrasing
Guest
I don't think it's even as simple as yes to the first. coils have an optimal range for a reason, you won't find a coil that performs as well at both 50 and 100 Watts and with such a wide margin there is a point of diminishing returns.
It's more accurate to say that with those variables you wouldn't be getting more nicotine, you would be getting the same amount of nicotine faster.
And then you also increase your chances of running into a couple of problems, if you put too little voltage through a coil you are likely to have poor vapour production and a high chance of leaking.
Too much voltage or wattage and you will degrade both the Coil and the wicking material much faster all the while producing the same or even less amount of nicotine infused vapour as if you use it correctly.
For example, if you use a coil that works best at 50w at 100w, yes you are going to produce more vapour short term but your wick and your coil will burn,
hypothetically if you double the power and the build lasts half a day, if you use the correct power for the coil, that same build would last several days and produce more, just over a longer time period.
It's more accurate to say that with those variables you wouldn't be getting more nicotine, you would be getting the same amount of nicotine faster.
And then you also increase your chances of running into a couple of problems, if you put too little voltage through a coil you are likely to have poor vapour production and a high chance of leaking.
Too much voltage or wattage and you will degrade both the Coil and the wicking material much faster all the while producing the same or even less amount of nicotine infused vapour as if you use it correctly.
For example, if you use a coil that works best at 50w at 100w, yes you are going to produce more vapour short term but your wick and your coil will burn,
hypothetically if you double the power and the build lasts half a day, if you use the correct power for the coil, that same build would last several days and produce more, just over a longer time period.
zouzounaki
Olympian
- Joined
- Dec 13, 2016
- Messages
- 36,128
Just vape the fkin thing....did you ever worry if some days you smoked 15 fags and another day 20 and another day 12.... no....so..
it’s a bit like fartin in a bag and trying to test the potency based on the duration. every wan is different so there’s nae use
Richard Winter
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- Apr 15, 2018
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- 5,011
Try looking at it another way. If you vape 10ml of e-liquid in one day at say 18mg nic strength, could be any strength you like, you will consume 180mg of nicotine in that one day.
If you lower your wattage and dont get thru the 10ml you wont consume as much nic. Same if you increase it.
Different pods/tanks/coils will all work slightly differently, some are more thirstier than others.
As @Rickster said, at the end of the day, does it really matter weather you consume 120mg of nic or 100mg in a day.
If you lower your wattage and dont get thru the 10ml you wont consume as much nic. Same if you increase it.
Different pods/tanks/coils will all work slightly differently, some are more thirstier than others.
As @Rickster said, at the end of the day, does it really matter weather you consume 120mg of nic or 100mg in a day.
Vapificator
Member
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- Aug 16, 2023
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- 7
Hello there,
I just registered because of this topic, because I find it rather interesting and I'd like to revive it.
Why?
Because figuring this out helps to not always needing to trial and error and instead just have a rough idea how to get the sensation of an average cig's nicotine into your vape or some (lower) percentage of it just only to get an idea.
So for what?
Using same juice at different wattages, in different device or knowing how many nic shots(mg/ml) to put into your shortfill for a given coil(resistance) and wattage
and to figure a conversion how a different setup would do different. I do not see why this couldn't be done, at least in a very rough way.
Some people might be satisfied to know a list of examples and extrapolate from there, but it would be really nice to find a rough rule of thumb formula,
which works for say typical industry coils with ignoring the slight differences of PG/VG used among ohm and sub-ohm vaping and all these "other factors".
In short:
Estimating a percentage or perceived nicotine sensation by having a liquid and changing parameters coil and wattage, eg. by comparing it to a traditional stinky cig's nic strength.
Don't you think it would be useful after all?
It should be possible to find a rule of thumb formula with inputs:
Wattage(watt), Resistance(ohm) and Nicotine concentration of your juice (mg/ml)
And the output:
"perceived strength" (mg/ml) per inhale
The problem could be simplified a lot, if we assumed a standard cig strength of 18mg/ml at 1ohm with 16 watt (in a typical industry MTL RTA tank/coil, which has nice numbers and is about what most people use)
and then retrieve a rough estimated "percentage of full cig pull per vape pull"(in %) based on this with a conversation rule/formula.
So all what would be left is wattage(watt) and resistance(ohm) to calculate a factor/percentage we can apply to a given juice concentration(mg/ml),
so we can use to figure how strong we would perceive this juice roughly as a percentage of a normal cig (18mg/ml, 1ohm, 16 watt).
Ohms law is pretty well known, but we just do not know how to apply it to this problem (yet).
On this topic the information available online is very scarce, confusing and partially even contradictionary, since false information is shared a lot too,
but many people seem to have a rough idea how strength scales with wattage and resistance, which makes me believe it should be a possibility.
I found this one, but it contains small mistakes and is quite a bit confusing:
And there is this one, which can be put into a simple formula, if you would multiply wattage while dividing resistance by the same factor:
https://www.e-cigarette-forum.com/threads/does-higher-wattage-stronger-nicotine-delivery.720431/
If this is true, it comes very close to a solution, and we'd just miss in what (mathematical) relation resistance and wattage are, when it comes to "perceived strength".
It could be something as simple as:
"Perceived Strength(mg/ml)" = K x "Juice Strength(mg/ml)" x "Wattage(watt)" / "Resistance(ohm)"
where K is some constant we just need to figure out by using any example(eg. 18mg/ml, 1ohm, 16 watt) and see how it extrapolates.
But this would require that wattage scales proportional, so like 60watts would be roughly twice the strength of 30watts (at fixed resistance)
and resistance scales inversely proportional, so 0.5 ohm twice the strength of 1ohm or say half resistance is double the strength (at fixed wattage).
However some people disagreed to these statements, so it might be not just this, but what is it then?
I do not have enough experience to know it myself yet, but we can only solve this,
if we can agree on how both things scale with each other in terms of strength to find a mathematical relation between them.
And if we do, we should be able to find a rough rule of thumb formula quite easily.
I hope this wall of text and talk of math didn't put too many people off, but instead inspired some enthusiasts.
If you know a link with a formula or figured something out by yourself that you works for you or you know how increasing wattage and lowering resistance relatively increases strength(as a formula), please share it.
That would be awesome!
Thank you for everyone who chewed through this entire bulk!
I just registered because of this topic, because I find it rather interesting and I'd like to revive it.
Why?
Because figuring this out helps to not always needing to trial and error and instead just have a rough idea how to get the sensation of an average cig's nicotine into your vape or some (lower) percentage of it just only to get an idea.
So for what?
Using same juice at different wattages, in different device or knowing how many nic shots(mg/ml) to put into your shortfill for a given coil(resistance) and wattage
and to figure a conversion how a different setup would do different. I do not see why this couldn't be done, at least in a very rough way.
Some people might be satisfied to know a list of examples and extrapolate from there, but it would be really nice to find a rough rule of thumb formula,
which works for say typical industry coils with ignoring the slight differences of PG/VG used among ohm and sub-ohm vaping and all these "other factors".
In short:
Estimating a percentage or perceived nicotine sensation by having a liquid and changing parameters coil and wattage, eg. by comparing it to a traditional stinky cig's nic strength.
Don't you think it would be useful after all?
It should be possible to find a rule of thumb formula with inputs:
Wattage(watt), Resistance(ohm) and Nicotine concentration of your juice (mg/ml)
And the output:
"perceived strength" (mg/ml) per inhale
The problem could be simplified a lot, if we assumed a standard cig strength of 18mg/ml at 1ohm with 16 watt (in a typical industry MTL RTA tank/coil, which has nice numbers and is about what most people use)
and then retrieve a rough estimated "percentage of full cig pull per vape pull"(in %) based on this with a conversation rule/formula.
So all what would be left is wattage(watt) and resistance(ohm) to calculate a factor/percentage we can apply to a given juice concentration(mg/ml),
so we can use to figure how strong we would perceive this juice roughly as a percentage of a normal cig (18mg/ml, 1ohm, 16 watt).
Ohms law is pretty well known, but we just do not know how to apply it to this problem (yet).
On this topic the information available online is very scarce, confusing and partially even contradictionary, since false information is shared a lot too,
but many people seem to have a rough idea how strength scales with wattage and resistance, which makes me believe it should be a possibility.
I found this one, but it contains small mistakes and is quite a bit confusing:
And there is this one, which can be put into a simple formula, if you would multiply wattage while dividing resistance by the same factor:
https://www.e-cigarette-forum.com/threads/does-higher-wattage-stronger-nicotine-delivery.720431/
If this is true, it comes very close to a solution, and we'd just miss in what (mathematical) relation resistance and wattage are, when it comes to "perceived strength".
It could be something as simple as:
"Perceived Strength(mg/ml)" = K x "Juice Strength(mg/ml)" x "Wattage(watt)" / "Resistance(ohm)"
where K is some constant we just need to figure out by using any example(eg. 18mg/ml, 1ohm, 16 watt) and see how it extrapolates.
But this would require that wattage scales proportional, so like 60watts would be roughly twice the strength of 30watts (at fixed resistance)
and resistance scales inversely proportional, so 0.5 ohm twice the strength of 1ohm or say half resistance is double the strength (at fixed wattage).
However some people disagreed to these statements, so it might be not just this, but what is it then?
I do not have enough experience to know it myself yet, but we can only solve this,
if we can agree on how both things scale with each other in terms of strength to find a mathematical relation between them.
And if we do, we should be able to find a rough rule of thumb formula quite easily.
I hope this wall of text and talk of math didn't put too many people off, but instead inspired some enthusiasts.
If you know a link with a formula or figured something out by yourself that you works for you or you know how increasing wattage and lowering resistance relatively increases strength(as a formula), please share it.
That would be awesome!
Thank you for everyone who chewed through this entire bulk!
D
Deleted member 54254
Guest
Doesn't work like that tbh.
Vapificator
Member
- Joined
- Aug 16, 2023
- Messages
- 7
So how does it work then (roughly)?
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