How does thinner wire compensate for reduced temperature...
It will cover less cotton, hence produce less vapour - even if this vapour is mysteriously warmer it will be diluted by proportionately more air entering the chamber and will become cooler because of it.
You're either stuck in the 'correct' resistance for MTL mentality, or just bored...
PS The resistance is just part of the equation. When using a regulated mod where you can select a specific wattage if you want a 16 watt vape and chose to use a 1 ohm kanthal coil and 4 volts you'll get a 16 watt vape, if you instead use a 0.5 ohm SS coil at 2.8 and a bit Volts you'll still get a 16 watt vape. 16 watts is 16 watts - a 4 volt 16 watt vape won't pull more current from the battery than the 2.8 something Volt16 Watt vape as the 2.8 volts will be sent to the coil at higher Amps to achieve 16 Watts - the buck boost circuitry calculates how to convert the voltage and current and tailors it accordingly. if you are under the impression that the resistance affects how much current is drained from a battery in a regulated mod you are mistaken - it is 100 per cent down to the wattage you select, any slight difference in operating the buck boost for the different Voltage output will be miniscule. The entire 'correct resistance for an MTL vape' if you aren't using a mech is 100 per cent horseshit - you may find it works for you with a specific gauge of Kanthal doesn't mean it is automatically the answer for every other wire available. Fixating on resistance and ignoring everything else seems rather blinkered to me.
You may have a point that one wire may be slightly less efficient if you decide to use a higher wattage, but if you find an extra watt or two provides a better vape then it's a sacrifice worth making. If you don't find it to be better - then all you've lost is a couple of quid for a small spool of wire.to find out if you like it or not